![]() The screenshot below shows what the original poster wanted using three different methods already mentioned in this thread and required no scripting whatsoever. In JMP I have never needed to script date-time computations as most things can be handled by either using a simple formula and setting the format of a column or otherwise resolved with the extensive set of date-time functions JMP provides for column formulas. ![]() ![]() Even then there was always the risk of someone getting a format issue. I have battled with date-time data in Excel for over a decade and often have to resort to VBA scripting to overcome Excel's shortcomings. I have lost count of the number of times that we have had to redo calculations in the past using Excel because of date-time format issues, but those problems disappeared once my analytical team began using JMP for analytics and became knowledgeable of how JMP handles date-times. The very fact that JMP, unlike Excel, has a duration time format has been a godsend for us. Due to the nature of our work, we deal with timing data extensively. I would not go as far as saying that your statement is blasphemy, but in my experience, JMP is orders of magnitude better at handling date-times than Excel. The following formula returns 1, the number of times a new hour started between the times:ĭate Difference(31Dec2010:23:59:59, 01Jan2011:00:59:59, "Hour", "start") Īlternatively you can run the following script and pay attention to the last comand with the formula of column 3.įormat( "Best", Use thousands separator( 0 ), 17 ),įormula( Date Difference( :Column 1, :Column 2, "day", "actual" ) ) The following formula returns 9, the number of completed hours between the times:ĭate Difference(01Jan2010:00:00:00, 01Jan2010:09:22:57, "Hour", "actual") The following formula returns 207, the number of completed days between the dates:ĭate Difference(01Jan2010:00:00:00, 27Jul2010:21:21:57, "Day", "actual") Start is used to count the number of times an interval starts.įractional is used to count fractional intervals.įor example, the following formula returns 207.890243055556, the number of days between the dates:ĭate Difference(01Jan2010:00:00:00, 27Jul2010:21:21:57, "Day", "fractional") The alignment arguments are described here: The interval argument can be Second, Minute, Hour, Day, Week, Month, Quarter, Year. Returns the difference of two datetime values. it is called Date difference and you can find it in the formula editor under "Date Time" functions. Add the days including any carried over from calculating hoursĪdd 2 days 21 hours 45 minutes 39 seconds to 5 days 10 hours 45 minutes 22 secondsĭivide days, hours, minutes and seconds by a divisor, working from smallest unit of time to largest.There is a designated formula just for that.If total hours is greater than 24, subtract 24 from hours and carry 1 to days.Add the hours including any carried over from calculating minutes.If total minutes is greater than 59, subtract 60 from minutes and carry 1 to hours.Add the minutes including any carried over from calculating seconds.If total seconds is greater than 59, subtract 60 from seconds and carry 1 to minutes.How to Add TimeĪdd days, hours, minutes and seconds working from smallest unit of time to largest. See examples of adding, subtracting, multiplying and dividing segments of time. How to do math operations with time is explained below. Answers include equivalent time in total days, hours, minutes or seconds. The calculator can add and subtract time segments or multiply and divide time by a number or decimal. Time calculator to add, subtract, multiply and divide time in days, hours, minutes and seconds. ![]()
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